Thread:FrostiesPrincess/@comment-4638690-20170406103306/@comment-4638690-20170406112651

Yes, I am a new user, but I'm sure that you've seen my username running wild in this Wikia the past few days because I've literally started editing everything (from characters to episodes to groups to adding new pages for organization sake, etc). If you checked the activity feed these past few days, it's only just me xD

I have to agree with you that Kaizo is indeed an antihero, but I just feel like that doesn't solely define him as a character. He is an antihero in the fact that he stands in the progress of the protagonist (BoBoiBoy and friends), but he has good intentions that don't necessarily meet up with the morals and ideals of BoBoiBoy. It's best to just keep the 'antihero' statement as a piece of trivia. As personally, I do find Kaizo to be relatively tall, compared to the rest of the cast that is, but I can see your point.

I've been doing quite a some of work on this Wikia. If you are skeptical of all the work I did, you are free to check my User Contributions and you can clearly see all the work I've done (I've even taken the time to give a brief summary of what I was doing each time I edited an article). I was the one responsible for adding all the summaries to Galaxy's episodes (which I am currently still in the progress of doing) and for some of the 'Galaxy Updates' to some of the character pages. I   feel like I would be able to contribute a lot to this Wikia if I was an admin, so I genuinely hope you are seriously considering me in for a position.

 Thanks for the reply and happy editing! Terbaik!

 P.S. As an English speaker, I can totally understand the struggles of learning English. English is a difficult language and even I have trouble with it sometimes. Nonetheless, I'd be able to help as a native English Speaker. Fun fact, I know Indonesian too so I can understand a portion of Malay because the languages are so similar! I believe my skills would be an excellent asset to your team if you wish so see it.

 - Jae (azurajae)